– MAY/JUNE EXPO
PHYSICS PRACTICAL
ANSWERS
========================
========
Exam Time: 09.30am –
12.15pm
NOTE: ^ means raise to
power
(1)
TABULATE:
i:1,2,3,4,5,
L(cm)
:80.00,70.00,60.00,50.00,40.00
t1(s)
:17.87,16.22,16.09,14.08,13.28
t2(2)
:17.56,16.46,15.09,14.77,13.36
t(s)
mean:17.715,16.340,15.590,14
.t(s)
mean:17.715,16.340,15.590,14
.425,13.320
T(t/10)
s:1.7715,1.6340,1.5590,1.4425
,1.3320
LogT(s)
:0.2483,0.2133,0.1928,0.1591,
0.1212
Log L(cm)
:1.9031,1.8451,1.7782,1.6990,
1.6021
Log T*10^-2(s)
:24.83,21.33,19.28,15.91,12.12
Log L*10^-1(cm)
:19.031,18.451,17.782,16.990,
16.021
SLOPE(s)=(LogT2*10^-2 –
LogT1*10^-2)(/Log L2
*10^-1 –
LogL1*10^-1)
=(21.33-12.12(s))*10^-2/
(18.50-16.02(cm)*10^-1)
=3.714*10^-1
=0.3714cm^-1
(1axi)
(i)ensured supports of
pendula were rigged
(ii)avoided parallax error on
meter rule/stop watch
(1bi)
simple harmonic motion is the
motion of a body whose
acceleration is always direct
towards a fixed point and is
proportional to the
displacement from the fixed
points
(1bii)
T=1.2secs
Log 1.2=0.079
0079 shown on graph with
corresponding Log L read L
correctly determined
================
3a)
PUT IN TABULAR FORM
x(cm):10,20,30,40,50,60
V(v)
:0.65,0.75,1.00,1.20,1.45,1.55
I(A):0.20,0.30,0.3I(A)
:0.20,0.30,0.35,0.40,0.45,0.55
LogV(v)
:-0.187,-0.125,0.000,0.079,0.
161,0.190
LogI(ohm)
:-0.699,-0.523,-0.456,-0.396,
-0.391,-0.360
SLOPE(s):=( LogI2-LOgI1)/
(LogV2-LogV1)
=-0.2-(-0.7)/0.3-(-0.2)
=0.5/0.5
=1AV^-1
(3axi)
(i)ensured clean/tight
terminals
(ii)open key when reading
was taken
(3bi)
(i)brightness of the bulb
increases
(ii)voltage/current through
the bulb increases
(3bii)
(i)diode
(ii)transistor
START INVITING YOUR
FRIENDS
